Simple Hearing Test
Reply #85 – 2008-08-22 05:43:15
If you "pretend you are a DAC" and "connect the dots", and add some smoothing (filtering), you don't get the original waveform. Please re-read my reply to your post. You do not understand how a DAC works nor how PCM works. Please stop posting this nonsense. See: http://www.dspguide.com/ch3/2.htm . It actually has an example almost exactly like Raiden's screenshot. From the text:[T]he situation is made more difficult by increasing the sine wave's frequency to 0.31 of the sampling rate. This results in only 3.2 samples per sine wave cycle. Here the samples are so sparse that they don't even appear to follow the general trend of the analog signal. Do these samples properly represent the analog waveform? Again, the answer is yes, and for exactly the same reason. The samples are a unique representation of the analog signal. All of the information needed to reconstruct the continuous waveform is contained in the digital data. Obviously, it must be more sophisticated than just drawing straight lines between the data points. As strange as it seems, this is proper sampling according to our definition. All we know is that the original waveform passed-through those data points The PCM samples are not voltage values that the original waveform passed through. They are impulses that allow the DAC to reproduce the original waveform. The PCM samples are taken after the Sample-and-Hold circuit and an anti-alias circuit and are not necessarily identical to the original waveform. They just happen to match closely when you're looking at waveforms much lower than Nyquist.